Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Find all real zeros of the function algebraically -5(x^2+2x-4)

Sagot :

Xignerso

[tex]−5(²+2−4)[/tex]

[tex]−5²−10+20[/tex]

Solution :—

[tex]−5²−10+20[/tex]

devishri1977

Answer:

Step-by-step explanation:

-5(x² + 2x - 4) = -5x² - 10x + 20

a = -4  ; b = -10  ; c = 20

D = b² - 4ac = (-10)² - 4*(-4)*20

   = 100 + 320 = 420

[tex]\sqrt{D}=\sqrt{2*2*3*5*7}=2\sqrt{105}\\\\x=\dfrac{-b+\sqrt{D}}{2a} \ ; x =\dfrac{-b-\sqrt{D}}{2a}\\\\\\x=\dfrac{10+2\sqrt{105}}{2*(-5)} \ ; \ x =\dfrac{10-2\sqrt{105}}{2*(-5)}\\\\\\x = \dfrac{2*(5+\sqrt{105})}{2*(-5)} ; \ x =\dfrac{2*(5-\sqrt{D})}{2*(-5)}\\\\\\x =\dfrac{5+\sqrt{105}}{-5} \ ; \ x=\dfrac{5-\sqrt{105}}{-5}\\\\\\x=\dfrac{-5-\sqrt{105}}{5} \ ; \ x =\dfrac{-5+\sqrt{105}}{5}[/tex]

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.