Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

the length of a rectangle is twice its width. find the area if its perimiter is 7 1/3 cm

Sagot :

Hmmm try asking someone for help

Answer:

Area = 2.99 cm2

Step-by-step explanation:

[tex]P=2l+2w[/tex]

If:

[tex]l=2w\\P=7\frac{1}{3} cm=\frac{22}{3} cm[/tex]

Then

[tex]\frac{22}{3} =2(2w)+2w[/tex]

[tex]\frac{22}{3} =6w[/tex]

[tex]\frac{22}{18} =w[/tex]

[tex]l=2w=2(\frac{22}{18} )=\frac{44}{18}[/tex]

lenght simplified=22/9

width simplified = 11/9

Area.

[tex]A=lw=(\frac{22}{9} )(\frac{11}{9} )=(\frac{242}{81} )=2.99cm^{2}[/tex]

Hope this helps