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What are the coordinates of the vertex of the graph of y = x^2 - 8x - 12?

Sagot :

Answer:

[tex](4,-28)[/tex]

Step-by-step explanation:

Recall that the x-coordinate of the vertex is [tex]x=-\frac{b}{2a}[/tex], therefore:

[tex]x=-\frac{b}{2a}[/tex]

[tex]x=-\frac{-8}{2(1)}[/tex]

[tex]x=4[/tex]

Now we find f(4) to get the y-coordinate of the vertex:

[tex]f(x)=x^2-8x-12[/tex]

[tex]f(4)=4^2-8(4)-12[/tex]

[tex]f(4)=16-32-12[/tex]

[tex]f(4)=-16-12[/tex]

[tex]f(4)=-28[/tex]

Therefore, the vertex of the graph is [tex](4,-28)[/tex]

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