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Sagot :
Each of the small pitcher will contain 4 cups of water while each of the large pitcher will contain 16 cups of water.
Therefore, two equal-sized large pitchers will hold 32 cups of water while the two equal-sized small pitchers will hold 8 cups of water
Larger Pitchers
The 2 larger pitchers are equal in size.
Let
each size of the large pitcher = x
Two large size pitcher = 2x
Smaller Pitchers
The 2 smaller pitchers are equal in size
let
each size of the pitcher = y
Two small sized pitchers = 2y
Pitchers Capacities
The whole pitchers holds 40 cups of water. Therefore,
- 2x + 2y = 40
The capacity of one large pitcher minus the capacity of one small pitcher is 12 cups. Therefore,
- x - y = 12
Combine the equations.
2x + 2y = 40
x - y = 12
x + y = 20
2y = 8
y = 8 / 2
y = 4
x - 4 = 12
x = 12 + 4
x = 16
learn more on geometry here: https://brainly.com/question/26109140?referrer=searchResults
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