Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

If (n+1) + (n+3) + (n+ 5) = 27, then 3n..?

Sagot :

Answer:

3n = 18

Step-by-step explanation:

(n + 1) + (n + 3) + (n + 5) = 27

Remove the bracket,

n + 1 + n + 3 + n + 5 = 27

Group like terms,

n + n + n + 1 + 3 + 5 = 27

Add similar elements,

3n + 9 = 27

Substrate 9 from both sides,

3n + 9 - 9 = 27 - 9

Simplify,

3n = 18

Simplify,

n = 6

We got the information, which n = 6.

3n = 3 × 6

= 18

Since all binomials inside the parenthesis are all only being multiplied by one, we can just get rid of all parenthesis forming the equation

n+1+n+3+n+5=27

And now we can combine like terms to form the equation

3n+9=27

Then you would subtract 9 from both sides and then we are left with

3n=18
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.