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Find the slope of a line that contains (0,3) and (5,-2)

Sagot :

felipesierra213

Answer:

The slope of the line is m = −1

The y-intercept is (0,3)

The equation of the line in the slope-intercept form is y = 3 − x

or y = -x + 3

 

Step-by-step explanation:

The slope of a line passing through two points P=(x1,y1) and Q=(x2,y2) is given by m=y2−y1 / x2−x1.

We have that x1 = 0, y1 = 3, x2 = 5, and y2 = −2.

Plug the given values into the formula for a slope: m = −2−3 / 5−0 = −1

or -5/5 =-1

Now, the y-intercept is b = y1 − mx1 (or b = y2 − mx2, the result is the same).

b = y-int

y1 = 3

m = slope = -1

x1 = 0

b = 3 − (−1) ⋅ (0) = 3

Finally, the equation of the line can be written in the form y = b + mx:

y = 3 − x

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