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Nick raises a 4-kg mass vertically 0.05 meters above his head. Determine the work done on the mass.

Sagot :

nuhulawal20

The work done by Nick as he raises the given mass over the given distance is approximately 2 Joules.

Given the data in the question:

  • Mass raised; [tex]m = 4kg[/tex]
  • Distance covered; [tex]d = 0.05m[/tex]

Work done; [tex]W = \ ?[/tex]

First we calculate the force used to raise the mass to the given distance.

Since the movement was vertical, the force must over come the mass and the pull of gravity ( [tex]g = 9.8m/s^2[/tex] ).

Using Newton's second law of Motion;

[tex]F = m * g[/tex]

We substitute our values into the equation

[tex]F = 4kg * 9.8m/s^2\\\\F = 39.2 kgm/s^2[/tex]

Now, we determine the work done by Nick.

Work done is simply the energy transferred from one store to another.

It is expressed as;

[tex]Work\ done = force * distance\\\\W = F * d[/tex]

So we substitute our values into the equation

[tex]W = 39.2kgm/s^2 * 0.05m\\\\W = 1.96kgm^2/s^2\\\\W = 2 J[/tex]

Therefore, the work done by Nick as he raises the given mass over the given distance is approximately 2 Joules.

Learn more about Newton's law of motion: https://brainly.com/question/20066791

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