Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
Explanation:
Stoichiometry is the quantitative study of the mass relation of reactants and products in a chemical reaction to determine the amount of reactant required for a reaction to produce a specified quantity or to determine the theoretical yield for the products.
The mole is an SI base unit to measure the amount of elementary entities (atom, molecules, ions, electrons, particles, etc.) of a given mass of a particular substance. One mole is the quantity of a substance exactly equal to Avogadro's number which is approximately 6.022 [tex]\times \ 10^{23} \ \ \text{mol}^{-1}[/tex].
For a stoichiometric calculation for gram-to-mole conversion, the conversion follows the relation
[tex]n \ = \ \displaystyle\frac{m}{M_{r}}[/tex],
where [tex]n[/tex] is the number of moles of a given substance, [tex]m[/tex] is the mass of the substance and [tex]M_{r}[/tex] is the molecular weight of the substance.
Given that the substance of interest is sodium chloride, NaCl, the molecular weight of the compound is
[tex]M_{r} \ = \ A_{r}(\text{Na}) \ + \ A_{r}(\text{Cl}) \\ \\ M_{r} \ = \ 23 \ + \ 35.45 \\ \\ M_{r} \ = \ 58.45 \ \text{g mol}^{-1}[/tex],
where [tex]A_{r}[/tex] is the atomic mass of the element.
Therefore, the number of moles of sodium chloride is
[tex]n \ = \ \displaystyle\frac{255 \ \text{g}}{58.45 \ \text{g mol}^{-1}} \\ \\ n \ = \ 4.363 \ \text{mol} \ \ \ \ \ \ \ \ (\text{4 \ s.f.})[/tex]
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.
