saurabhmehta98505
Answered

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A long spring is strecthed by 2cm and it's potential energy is v. If the spring is stretched by 10 cm it's potential energy will be ?​

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ItsYourDeepak254

Answer:

Hey There!

Let's solve....

[tex]v = \frac{1}{2} k{x}^{2} \\ \\ \frac{ v_{1} }{ v_{2} } = (\frac{ x_{1} }{ x_{2}}) ^{2} \\ \\ \frac{v}{ v_{2} } =( \frac{ \cancel{2}}{ \cancel{10 }}) ^{2} \\ \\ = \frac{1}{25} \\ \\ v_{2} = 25v_{1} \\ \\ = 25v [/tex]

I hope it is helpful to you...

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