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A gas sample has a volume of 248L at 298 K. What is the volume of the gas at 398K?

Sagot :

devil0184
V1 = 248L
V2= X
T1= 298K
T2= 398K
V1/T1 = V2/T2 (Charles law)
248/298 = X/398
Cross multiply
298X = 398 x 248
298X = 98704
Divide through by the coefficient of X
X = 98704/298
X = 331.22 (to 2 dp)
Therefore, V2 = 331.22L
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