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The tempeture of chicken soup is 192.7 degrees F. As it cools the tempeture of the soup decreases 2.3F per minute.
PART A: What is y=the tempeture of the soup ater 25 minutes?
PART B: How many minutes will it take for the soup to cool to 100.7F

Sagot :

alecair

Answer:

Step-by-step explanation:

To find the answer to Part A, we can turn this into a simple equation:

192.7 - (2.3 times 25) = temperature, the missing value.

So therefore, after 25 minutes pass, the temperature is equal to

192.7 - 57.5, or:

135.2 = Answer to Part A.

Now, onto Part B. We can use another equation!

192.7 - 2.3x = 100.7

Now, we must solve the given equation, first by taking 100.7 from each side:

192.7 - 2.3x = 100.7

-100.7             -100.7

We are now left with: 92 - 2.3x = 0 - we must now add 2.3x to 2.3x and 0, giving us this:

92 = 2.3x, which is equivalent to 920 = 23x, if that is what you prefer to solve.

To give us our missing value (x), we can divide 920 by 23, giving us: x = 40. This is the answer to Part B: 40 minutes.

I hope this was really helpful! Tell me if you need any more help.

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