marcuscheeatow
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What is an equation of the line that passes through the points (1, 2)(1,2) and (2, -1)(2,−1)?

Sagot :

abiafalak8

Answer:

y = -3x + 4

Step-by-step explanation:

First, we find the slope, and to find the slope;[tex]\frac{y_{2} - y_{1}}{x_{2} - x_{1} }[/tex]

Slope : -3

Now we fill in the equation with a point and find the y- intercept:

2 = -3(1) + b

2 = -2 + b

4 = b

y = -3x + 4

SpiritInly

Answer:

[tex]y = - 3x + 5[/tex]

Step-by-step explanation:

to find the gradient/slope between these points:

[tex]\frac{y_{2} - y_{1}}{x_{2} - x_{1} } [/tex]

[tex] \frac{ - 1 -2}{2 - 1} = - 3[/tex]

the gradient is -3

we need to write the equation in the form y=mx+c. Choose any of the two coordinates in the question. I'll choose (1,2).

y is 2, x is 1 and m is the gradient which is -3

working out c:

[tex]y = mx + c[/tex]

[tex]2 = - 3(1) + c[/tex]

[tex]2 = - 3 + c[/tex]

add 3 on both sides

[tex]2 + 3 = c[/tex]

[tex]c = 5[/tex]

final equation:

[tex]y - = - 3x + 5[/tex]

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