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2) If a heptagon has an area of 105 in^2, what is the measure of one side? (1 pt.)

Sagot :

Answer:

5.375 in. to the nearest thousandth.

Step-by-step explanation:

Area of a regular heptagon

= 7/4 * cot(pi/7) * s^2    where s is the length of one side.

105 = 7/4 * cot(pi/7) * s^2

s^2  = 105 / (7/4 cot (pi/7)

       = 28.8945

s = sqrt 28.8945

  = 5.375 in.

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