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Sagot :
Answer:
F(Mars) = 2 G m M / (4 R)^2 force of Sun on Mars
F(Merc) = G m M / R^2 force of force of Sun on Mercury
R = distance of Sun from Mercury, m = mass of Mercury
F(Merc) / F(Mars) = 4^2 / 2 = 8
The ratio of the gravitational force from the Sun on Mercury to the gravitational force from the Sun on Mars will be 8.
What is gravitational force?
Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
[tex]F = \frac{GmM}{r^2} \\\\[/tex]
If Mars has twice the mass of Mercury and is 4 times further away from the Sun. Gravitational force from the Sun on Mercury is;
[tex]\rm F_{mars}=\frac{2Gmm}{4r^2} \\\\[/tex]
The gravitational force from the Sun on Mars;
[tex]\rm F_{mars} = \frac{GmM}{r^2} \\\\[/tex]
[tex]\frac{F_{mercury}}{F_{mars}} = \frac{4^2}{2} \\\\ \frac{F_{mercury}}{F_{mars}} = 8[/tex]
Hence,the ratio of the gravitational force from the Sun on Mercury to the gravitational force from the Sun on Mars will be 8.
To learn more about the gravitational force, refer to the link;
https://brainly.com/question/24783651
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