Answered

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Write the equation of a line that contains the point (1,5) and is perpendicular to the
line y = 2x - 6.

Sagot :

Slope of line that is perpendicular to the  line y = 2x - 6,

[tex]m=-\dfrac{1}{2}[/tex]

Line passes through (1,5).

Equation of line will be,

[tex]y-5=m(x-1)\\y-5=-1/2{x-1}\\2y-10=-x+1\\2y=11-x[/tex]

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