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How do you balance C4H10 + Cl2 + O2 —> CO2 + CCl4 + H2O?

Sagot :

Answer:

4C4HO + 4Cl2 + 13O2 → 14CO2 + 2CCl4 + 2H2O

Explanation:

Balance The Equation: C4HO + Cl2 + O2 = CO2 + CCl4 + H2O

1. Label Each Compound With a Variable

  aC4HO + bCl2 + cO2 = dCO2 + fCCl4 + gH2O

2. Create a System of Equations, One Per Element

  C: 4a + 0b + 0c = 1d + 1f + 0g

  H: 1a + 0b + 0c = 0d + 0f + 2g

  O: 1a + 0b + 2c = 2d + 0f + 1g

  Cl: 0a + 2b + 0c = 0d + 4f + 0g

3. Solve For All Variables

  a = 4

  b = 4

  c = 13

  d = 14

  f = 2

  g = 2

4. Substitute and Verify Result

  4C4HO + 4Cl2 + 13O2 = 14CO2 + 2CCl4 + 2H2O

      L R

  C: 16 16 ✔️

  H: 4 4 ✔️

  O: 30 30 ✔️

  Cl: 8 8 ✔️

hope this helps! :D

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