Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
Using algebraic equations:
the number of sessions that will give same cost for both plans is: 1
the cost is: $96
Translate the situation into algebraic equations.
- Let y = Total cost
- x = number of sessions
Equation for total cost of the first plan:
y = 41x + 55
Equation for the total cost of the second plan:
y = 46x + 50
To find the number of sessions that would yield same cost for both plans, make both equations equal to each other and solve for x.
41x + 55 = 46x + 50
- Combine like terms together
41x - 46x = - 55 + 50
-5x = -5
x = 1
For a session, both plans will yield the same cost.
The cost 1 session will yield for both:
41x + 55 = 46x + 50
- Plug in the value of x
41(1) + 55 = 46(1) + 50
96 = 96
Therefore, using algebraic equations:
the number of sessions that will give same cost for both plans is: 1
the cost is: $96
Learn more about algebraic equations on:
https://brainly.com/question/10612698
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.