Answered

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2. A high school wants to double the size of its parking lot by expanding the existing lot as
shown below. By what distance should the lot be expanded?
x ft
kin
75ft
old parking lot
165ft
school
300 Ft
75 ft xft

Sagot :

The parking lot is located along the front and one side of the school

building.

  • The distance x with which the lot should be expanded is 60 feet.

Reasons:

The given dimensions in the compound are;

Length of the school and the old parking lot = 300 + 75

Width of the school and the old parking lot = 165 + 75

Length of the school, the old and new parking lot = 300 + 75 + x

Width of the school and the old and new parking lot = 165 + 75 + x

Area of the new parking lot the school wants = Double the old parking lot

In terms of areas, we have;

New compound - School = 2 × (old compound - school)

Which gives;

(300 + 75 + x) × (165 + 75 + x) - 300 × 165 = 2 × ((300 + 75) × (165 + 75) - 300 × 165)

2 × (375 × 240 - 49,500) = (375 + x) × (240 + x) - 49,500

Simplifying gives;

81,000 = x² + 615·x + 40,500

x² + 615·x + 40,500 - 81,000 = 0

x² + 615·x - 40,500 = 0

Factorizing with a graphing calculator gives;

(x - 60)·(x + 675) = 0

Therefore;

x = 60 or x = -675

Given that x is a natural number, we have, the correct value is; x = 60;

The distance with which the lot should be expanded, x = 60 feet.

Learn more about writing equations here:

https://brainly.com/question/20475360

https://brainly.com/question/7107994

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