prantoscollos
Answered

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Solve 2x^2 - x ≥ -5. Show your work.

Sagot :

Answer:

[tex](x-\frac{1}{4})^{2} \geq \frac{-39}{16}[/tex]

Step-by-step explanation:

Rewrite into standard form:

[tex]2x^{2} -x+5 \geq 0[/tex]

Complete the square:

[tex]2(x-\frac{1}{4} )^{2} + \frac{39}{8} \geq 0[/tex]

Subtract [tex]\frac{39}{8}[/tex] from both sides:

[tex]2(x-\frac{1}{4})^{2} \geq \frac{-39}{8}[/tex]

Divide both sides by 2:

[tex](x-\frac{1}{4})^{2} \geq \frac{-39}{\frac{8}{2}}[/tex]

Simplify:

[tex](x-\frac{1}{4})^{2} \geq \frac{-39}{16}[/tex]

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