Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Ask your questions and receive precise answers from experienced professionals across different disciplines. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Answer:
Slope is [tex]-\frac{1}{2}[/tex]
Step-by-step explanation:
Given:
[tex]f(x)=-3\sqrt{x}[/tex]
Find the derivative using the product rule:
[tex]f'(x)=\frac{d}{dx}(-3)*\sqrt{x}+-3*\frac{d}{dx}\sqrt{x}[/tex]
[tex]f'(x)=-3*\frac{1}{2\sqrt{x}}[/tex]
[tex]f'(x)=\frac{-3}{2\sqrt{x}}[/tex]
Plug in coordinates to find slope at that point:
[tex]f'(9)=\frac{-3}{2\sqrt{9}}=\frac{-3}{2(3)}=\frac{-3}{6}=-\frac{1}{2}[/tex]
Therefore, the slope of the equation at the point (9,-9) is [tex]-\frac{1}{2}[/tex].
Answer:
Step-by-step explanation:
f(x) = -3√x
f'(x) = -1.5/√x
f'(x) = -1.5/√9
f'(x) = -1.5/3
f'(x) = -0.5
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.
