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What is the equation of the line with a slope of 4 and passes through the point (1, -4)?

Sagot :

amarlashri

Answer:

y=4x-8

Step-by-step explanation:

m=4 (1,-4)

-4=4(1) + c

-4=4+c

-4-4=c

-8=c

y=4x-8

Answer: y = 4x - 8

Step-by-step explanation:

The best way to go about this is to first put the information you know into point-slope form, which is:

[tex]y-y_{1} =m(x-x_{1})[/tex]

[tex]y_{1}[/tex] and [tex]x_{1}[/tex] represent the values of our point (1, -4), so:

[tex]y_{1}=-4[/tex], and [tex]x_{1}=1[/tex].

[tex]m[/tex] represents our slope of 4, so:

[tex]m=4[/tex]

From this, we can plug in our values:

[tex]y-(-4)=4(x-1)[/tex]

A little simplification and distrobution takes us to this:

[tex]y+4=4x-4[/tex]

Then simply subract 4 from both sides to get this:

[tex]y=4x-8[/tex]

An easier way to reason this is to visualize the line in your head and figuring out what the y-intercept is so you can go strait into the [tex]y=mx+b[/tex] form where b is the y-intercept.

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