butts36
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What is the equation of the line that passes through the point (8,-4) and has a slope of 1/2

Sagot :

SenorMathWiz

Answer:

y = 1/2x - 8

Step-by-step explanation:

Assuming that they want the equation in slope intercept form we would use the following form: y = mx + b

where m = slope and b = y intercept.

We are given the slope and a point on the line. We need to find the y intercept. We can do this by plugging in what we are given and then solving for b.

y = mx + b

slope (m) = 1/2

x value of given point (x) = 8

y value of given point (y) = -4

- plug in these values -

-4 = (1/2)(8) + b

now solve for b

multiply 1/2 and 8

-4 = 4 + b

subtract 4 from both sides

-8 = b

So the y intercept (b) is -8

We now plug in the slope and y intercept into slope intercept form

y = mx + b

m = 1/2 and b = -8

y = 1/2x - 8 is the equation of the line that passes through the point (8,-4) and has a slope of 1/2

For more validation refer to the attached image.

View image SenorMathWiz
loneguy

[tex]\text{Given that,}\\\\(x_1,y_1) = (8,-4), ~~ \text{and slope, m} = \dfrac 12\\\\\text{Equation with given points,}\\\\y -y_1 = m(x-x_1)\\\\\implies y -(-4) = \dfrac 12 (x-8)\\\\\implies y+4 = \dfrac 12 x - 4\\\\\implies y= \dfrac 12x -4 -4 \\\\\implies y = \dfrac 12 x -8\\\\\implies y = \dfrac{x-16}2\\\\\implies 2y = x -16\\\\\implies x -2y = 16[/tex]

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