Answered

Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.


A bag contains 7 marbles: 4 red, 2 yellow, and 1 green. Three
marbles are to be selected from the bag, one at a time, without
replacement. If the order of selection does not matter, how many
color combinations of the three marbles are possible?

Sagot :

121159

Answer:

Step-by-step explanation:

you have 7 reds of 14 total.

the 1st marble has 7 of 14 probability of being red

the 2nd has 6 of 13 of being red

the 3rd has 5 of 12 of being red

multiplying this out you have:

(7/14)*(6/13)*(5/12)=210/2184

THAT will condense down to 5/52 or 9.615%

this does assume not placing the balls back in between draws

if you do put them back in between draws you would have 7 of 14 chance each draw

that would give you by multiplying out

(7/14) * (7/14)* (7/14) = 343/2744

Found it online lol

that condenses to 1 of 8 or 12.5%

Found it online lol

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.