Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
The mass of HgO needed for the reaction is 216 g
The correct answer to the question is Option C. 216 g
We'll begin by calculating the theoretical yield of Hg.
- Actual yield of Hg = 100 g
- Percentage yield = 50%
- Theoretical yield of Hg =?
Theoretical yield = Actual yield / percentage yield
Theoretical yield = 100 / 50%
Theoretical yield of Hg = 200 g
Finally, we shall determine the mass of HgO needed for the reaction.
2HgO → 2Hg + O₂
Molar mass of HgO = 201 + 16 = 217 g/mol
Mass of HgO from the balanced equation = 2 × 217 = 434 g
Molar mass of Hg = 201 g/mol
Mass of Hg from the balanced equation = 2 × 201 = 402 g
From the balanced equation above,
402 g of Hg were produced from 434 g of HgO.
Therefore
200 g of Hg will be produce by = (200 × 434) / 402 = 216 g of HgO.
Thus, 216 g of HgO is needed for the reaction.
Learn more about stoichiometry:
https://brainly.com/question/24426334
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.