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What is the number of ions in 0.20 mol of (NH4)3PO4?

Sagot :

The number of ions in 0.20 mole of (NH₄)₃PO₄ is 1.204×10²³ ions

From Avogadro's hypothesis,

1 mole of (NH₄)₃PO₄ = 6.02×10²³ ions

  • With the above information in mind, we can determine the number of ions in 0.20 mole of (NH₄)₃PO₄ as illustrated below:

1 mole of (NH₄)₃PO₄ = 6.02×10²³ ions

Therefore,

0.20 mole of (NH₄)₃PO₄ = 0.2 × 6.02×10²³

0.20 mole of (NH₄)₃PO₄ = 1.204×10²³ ions

Thus, 1.204×10²³ ions are present in 0.20 mole of (NH₄)₃PO₄

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