jmax17
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can someone please help me solve for x? i already have y

Can Someone Please Help Me Solve For X I Already Have Y class=

Sagot :

Step-by-step explanation:

[tex] \frac{3}{9} = \frac{5}{y} = \frac{x}{12} \\ \frac{3}{9} = \frac{5}{y} \\ 3y = 45 \\ y = 15 \\ \\ \frac{3}{9} = \frac{x}{12} \\ 9x = 36 \\ x = 4[/tex]