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gina wilson unit 4 homework 11

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abidemiokin

The required solution in terms of k is (k, (k-2)/2)

From the diagram, we are given the simultaneous equation expressed as:

-4y = -2x + 8 ................ 1

3x - 6y = 6

x - 2y = 2 ......................... 2

From equation 2, x = 2 + 2y ............... 3

Substitute equation 3 into 1 to have:

-4y =  -2(2+2y) + 8

-4y = -4 -4y + 8

-4y + 4y = -4 + 8

0y = 4

y = 4/0

y = ∞

This shows that the systems of equations have infinite number of solution.

Let x = k

x = 2 + 2y

k = 2 + 2y

2y = k - 2

y = (k-2)/2

Hence the required solution in terms of k is (k, (k-2)/2)

Learn more on simultaneous equation here: https://brainly.com/question/386828

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