Answered

Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Resultant Force Forces with magnitudes of
125 newtons and 300 newtons act on a hook (see
figure). The angle between the two forces is 45°. Find
the direction and magnitude of the resultant of these
forces. (Hint: Write the vector representing each force
in component form, then add the vectors.)

Sagot :

onyebuchinnaji

The resultant of the two forces is 398.32 N and the direction is 12.8⁰.

The given parameters:

  • first force, F₁ = 125 N at 45⁰
  • second force, F₂ = 300 N at 0⁰

The vertical component of the forces is calculated as;

[tex]F_y = 125 \times sin(45) \ + \ 300 \times sin(0)\\\\F_y = 88.388 \ N[/tex]

The horizontal component of the forces is calculated as follows;

[tex]F_x = 125 \times cos(45) \ + \ 300 \times cos(0)\\\\F_x = 388.388 \ N[/tex]

The resultant of the two forces is calculated as follows;

[tex]F = \sqrt{F_y^2 + F_x^2} \\\\F = \sqrt{88.388^2 + 388.388^2} \\\\F = 398.32 \ N[/tex]

The direction of the forces is calculated as follows;

[tex]\theta = tan^{-1} (\frac{F_y}{F_x} )\\\\\theta = tan^{-1}(\frac{88.388}{388.388} )\\\\\theta = 12.8\ ^0[/tex]

Learn more about resultant forces here: https://brainly.com/question/11194858

View image onyebuchinnaji
We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.