CoolBeans0903
Answered

Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

BRAINLIEST and please show your work!





Solve for x using the formula y = x^2 (2+4); when y = 2

Sagot :

loneguy

[tex]y =x^2(2+4)\\\\\implies 2= 6x^2 \\\\\implies x^2 = \dfrac 26 = \dfrac 13\\\\\implies x = \pm\dfrac 1{\sqrt 3}[/tex]

[tex]\text{Hence}~ x = \dfrac 1{\sqrt 3} ~\text{or}~ ~ x = -\dfrac 1{\sqrt 3}[/tex]

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.