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A hot-air balloon is 1550 feet off the ground and its altitude is slowly changing at a constant rate of −712 feet per second.

How many seconds, s, will it take for the balloon to drop to below 465 feet?

Drag and drop a symbol and value to correctly complete the solution to this inequality.
( K12 )

Sagot :

Building and solving an equation to model the situation, it is found that it will take 1.52 seconds for the balloon to drop to below 465 feet.

  • The initial height is of 1550 feet.
  • Each second, the height decreases by 712 feet.

Hence, the equation that models the height of the balloon after t seconds is:

[tex]h(t) = 1550 - 712t[/tex]

To find how many seconds, s, will it take for the balloon to drop to below 465 feet, we have to find t for which h(t) < 465, hence:

[tex]h(t) < 465[/tex]

[tex]1550 - 712t < 465[/tex]

[tex]712t > 1085[/tex]

[tex]t > \frac{1085}{712}[/tex]

[tex]t > 1.52[/tex]

It will take 1.52 seconds for the balloon to drop to below 465 feet.

A similar problem is given at https://brainly.com/question/25290003

gkmimaroglu

Answer:

s > 144 2/3

Step-by-step explanation:

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