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The mass of a sample of nickel (average atomic mass 58.69 u) is 11.74 g. How many atoms
does it contain?

Sagot :

nichealw9

the answer is 1.2 x 10^23

The number of atoms present in 11.74 g of nickel sample is 1.2 × 10²³.

What is Avogadro's number?

Avogadro's number is the number of entities present in one mole of any substance and its value is equal to 6.022 × 10²³.

Given that mass of nickel sample = 11.74g

Atomic mass of nickel sample = 58.69amu

Moles of this sample will be calculated as:

n = 11.74g / 58.69g/mol = 0.200 moles

No. of atoms in 0.200 moles = 0.200 × 6.022 × 10²³ = 1.2 × 10²³

Hence, required no.of atoms are 1.2 × 10²³.

To know more about Avogadro's number, visit the below link:

https://brainly.com/question/10614569

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