Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Join our platform to get reliable answers to your questions from a knowledgeable community of experts. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Answer:
7.20 X 10^-2 gm
Explanation:
Aqueous hydrobromic acid HBr will react with solid sodium hydroxide NaOH to produce aqueous sodium bromide NaBr and liquid water H2O. Suppose 3.24 g of hydrobromic acid is mixed with 2.3 g of sodium hydroxide. Calculate the maximum mass of water that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.
HBr(aq) + NaOH (S)-----------> NaBr (aq) + H20
mol wt of HBr = 1 + 79.9 = 80.9
3,24 gm of HBr = 3.24/80.9 = 0.00400moles = 4.00 X 10^-3 moles
mol wt of NaOH = 23.0 + 16.0 +1.01 = 40.0 gm
2.3 gm = 2.3/40.0 = 0.058 moles =5.8 X 10^-2
the reaction of HBr and NaOH is 1:1.
there are not enough moles of HBr to neutralize all of the NaOH. so
only 4.00X10 ^-3 moles of H2O can be produced
mol weight of H2O is (2 X 1.01) + 16.0 = 18.0
The maximum mass of H2O that can be produced is
18.0 X 4.00X10^-3 = 72.0/1000 =7.20 X 10^-2 gm
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.
