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A rope 63 feet long is cut into two pieces. One of the pieces is three times longer than the other piece. Which system of equations yields the length of the short rope, s, and the long rope, l?
A) s + l = 63 l = 3s
B) s + l = 63 s = 3l
C) s + l = 63(3) l = 3s
D) s + l = 63(3) s = 3l

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The system of equations that yields the length of the short rope, s, and the long rope, l will be A. s + l = 63 l = 3s

Based on the information given in the question, the equation to use will be:

l = 3s ...... i

s + l = 63 ...... ii

Substitute equation i into ii

s + l = 63

s + 3s = 63

4s = 63

s = 63/4

s = 15.75

l = 3s = 3 × 15.75 = 47.25

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Answer:

s+l= 63

l=3s

Step-by-step explanation:

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