user1828281
Answered

Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

given that R=0.0821 (L•atm) / (mol•K) how many moles must be in a 2L container at 1.8 atmospheres with a temperature of 270K

Sagot :

Eduard22sly

The number of mole in the container at 1.8 atm with a temperature of 270 K is 0.162 mole.

From the question given above, the following data were obtained:

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) = 2 L

Pressure (P) = 1.8 atm

Temperature (T) = 270 K

Number of mole (n) =?

Using the ideal gas equation, we can obtain the number of mole in the container as illustrated below:

PV = nRT

1.8 × 2 = n × 0.0821 × 270

3.6 = n × 22.167

Divide both side by 22.167

n = 3.6 / 22.167

n = 0.162 mole

Therefore, the number of mole in the container is 0.162 mole

Learn more: https://brainly.com/question/9731218

Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.