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In a box there are 6 orange balls, 4 green balls and blue "x" balls. If the probability of drawing one blue ball is 1/3, what is the probability of drawing two blue bags?

Sagot :

27tristenjones

Answer:

Correct option is

A

10

Let number of blue balls in the bag =x

Total no of balls in bag =5+x  [No. of redball =5]

Probability of drawing a blue ball =

Total no of ball

No. of blue ball

​

P(B)=

5+x

x

​

Probability of drawing a Red ball =

Total no of ball

No. of red ball

​

P(R)=

5+x

5

​

Given,

P(B)=2P(R)

5+x

x

​

=2(

5+x

5

​

)

x=10

​

Hence, no. of blue balls in the bag =10.

Step-by-step explanation:

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