Answered

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(b). Find the values of a and b that make f continuous everywhere.
X^2+6x + 5/x^2-3x-4, X<-1
ax^2- bx +3, -1<=x<=3
2x-a+b, x>=3

Sagot :

Answer:

a=-13/10

b=-5/2

Step-by-step explanation:

View image kauyujo
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