Answered

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8. If 100 grams of Au-198 decays to 6.25 grams in 10.8 days, what is the half-life of Au-198?

Sagot :

Answer: 2.7 days

Explanation:

You'd divide 100 g by 2 until you reach 6.25 g:

100/2

=

50

;

50/2 (fraction

=

25

;

25/2(fraction

=

12.5

;

12.5/2 (fraction

=

6.25

Since there were four 2s, divide 10.8 days by 4:

10.8 days

4

=

2.7 days

100 g of Au-198 would have a half life of 2.7 days.

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