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Sagot :
Using the binomial distribution, it is found that there is a 0.81 = 81% probability that NEITHER customer is selected to receive a coupon.
For each customer, there are only two possible outcomes, either they receive the coupon, or they do not. The probability of a customer receiving the coupon is independent of any other customer, which means that the binomial distribution is used to solve this question.
Binomial probability distribution
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- For each customer, 10% probability of receiving a coupon, thus [tex]p = 0.1[/tex].
- 2 customers are selected, thus [tex]n = 2[/tex]
The probability that neither receives a coupon is P(X = 0), thus:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{2,0}.(0.1)^{0}.(0.9)^{2} = 0.81[/tex]
0.81 = 81% probability that NEITHER customer is selected to receive a coupon.
A similar problem is given at https://brainly.com/question/25326823
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