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What mass in grams of dextrose (C 6H 12O 6) will be required to produce 3.00 L of a 0.35M aqueous solution

Sagot :

Answer:

1.05 X 180 = 189 gm of dextrose                                      

Explanation:

What mass in grams of dextrose (C 6 H 12 O 6) will be required to produce 3.00 L of a 0.35 M aqueous solution

the molar mass of (C 6 H 12 O 6)  is

(6 X 12) + (1 X 12) + (6 x 16) =

72 +12 + 96=

180 g/mol

we need 3 L x 0.35 moles/L =    1.05 moles of dextrose

so

1.05 X 180 = 189 gm of dextrose                                      

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