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prove that SinA×tanA/1-CosA=1+secA​

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aiesharehana

answer in the image....

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Answer:

Below.

Step-by-step explanation:

SinA×tanA/1-CosA

As tanA = sinA / cos A we have

sin^2A / cosA(1 - cosA)

= (1 - cos^2A) /  cosA(1 - cosA)

= (1 - cosA)(1 + cosA) / cosA(1 - cosA)

= (1 + cosA) /cos A

= 1 + 1/cosA

= 1 + secA.

=

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