Answer:
Perimeter:
= 58 m (approximate)
= 58.2066 or 58.21 m (exact)
Area:
= 208 m² (approximate)
= 210.0006 or 210 m² (exact)
Step-by-step explanation:
Given the following dimensions of a rectangle:
length (L) = [tex]\sqrt{252}[/tex] meters
width (W) = [tex]\sqrt{175}[/tex] meters
The formula for solving the perimeter of a rectangle is:
P = 2(L + W) or 2L + 2W
The formula for solving the area of a rectangle is:
A = L × W
Approximate Forms:
In order to determine the approximate perimeter, we must determine the perfect square that is close to the given dimensions.
13² = 169
14² = 196
15² = 225
16² = 256
Among the perfect squares provided, 16² = 256 is close to 252 (inside the given radical for the length), and 13² = 169 (inside the given radical for the width). We can use these values to approximate the perimeter and the area of the rectangle.
P = 2(L + W)
P = 2(13 + 16)
P = 58 m (approximate)
A = L × W
A = 13 × 16
A = 208 m² (approximate)
Exact Forms:
L = [tex]\sqrt{252}[/tex] meters = 15.8745 meters
W = [tex]\sqrt{175}[/tex] meters = 13.2288 meters
P = 2(L + W)
P = 2(15.8745 + 13.2288)
P = 2(29.1033)
P = 58.2066 or 58.21 m
A = L × W
A = 15.8745 × 13.2288
A = 210.0006 or 210 m²
