Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

The length of a rectangle is 3 feet more than 5 times its width. The perimeter of the rectangle is 42 feet.

Write an equation that can be used to find the width (w) of the rectangle and solve the equations


Sagot :

42 = 2(W+L)

21= (W+L)

L= 3+5W)

21= W +(3+5W)

21= 3+6W

21-3=6W

18=6W

W=18/6

=3

Answer:

w = PERIMETER/2 - LENGTH

w = 42/2 - (3+5w)

PS. I THINK THIS IS RIGHT. NOT TOO SURE, BUT MOST LIKELY.