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What is the equation of a line that passes trough (6,-1) and is parallel to the line that has a slope of -2/3?

Sagot :

Justin975

Answer:

y=-2/3x+3

Step-by-step explanation:

First, identify the slope you need for your equation. The keyword here is "parallel" so the slope you need is the same as the given slope (-2/3).

Next, use the ordered pair (6,-1); it's on the line that you need to find the equation for. Using slope-intercept form (y=mx+b), plug the -1 in for y, plug the 6 in for x, and plug in your slope of -2/3 for m. Solve for b, your y-intercept. You should get 3.

You have your slope and y-intercept now. Create your equation:

y=-2/3x+3.

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