Answered

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If an object starts with a velocity of 5.26 m/s

and ends with a velocity of 60.7 m/s in 15.0

seconds, what is its displacement?

Sagot :

namwanjemacklineeliz

Answer:

Displacement = 8.4m

Explanation:

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Have a great day.

[tex]v = 60.7m {s}^{ - 1} \: u \: = 5.26m {s}^{ - 1 } \: t = 15s \: \: \: \: \: \\ a \: = \frac{v - u}{t} \\ a \: = \frac{60 .7- 5.26}{15} \\ a = 3.7m {s}^{ - 28} \\ {v}^{2} = {u}^{2} + 2as \\ {60.7}^{2} = {5.26}^{2} + 2 \times 3.7 \times s \\ 60.7 =27 .7 + 2 \times 3.7s \\60.7 = 29.7 \times 3.7s \\ 60.7 - 29.7 = 3.7s \\ 31 = 3.7s \\ \frac{31}{3.7} = \frac{3.7s}{3.7} \\ s = 8.4m[/tex]

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