Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
The acceleration of the skier over the distance traveled is 10.38 m/s²
The given parameters;
- Initial velocity of the skier, u = 56 m/s
- Distance covered by the skier, s = 151 m
Acceleration is defined as the change in velocity per change in time of motion.
The magnitude of the acceleration of the skier is calculated as follows;
[tex]v^2 =u^2 - 2as\\\\[/tex]
where;
v is the final velocity at the end of 151 m = 0
[tex]0 = 56^2 -(2\times 151)a\\\\302a = 3136\\\\a = \frac{3136}{302} \\\\a = 10.38 \ m/s^2[/tex]
Thus, the acceleration of the skier over the distance traveled is 10.38 m/s²
Learn more here:https://brainly.com/question/20453233
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.