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a summer speeds up from 1.1m/s to 1.3m/s during the last 20 s of the workout. what is the acceleration during this interval

Sagot :

Answer:

acceleration= 0.01 m/s²

Explanation:

[tex]a = \frac{v - u}{t} [/tex]

[tex]a = \frac{1.3 - 1.1}{20} [/tex]

[tex]a = \frac{0.2}{20} [/tex]

[tex]a = 0.01 \frac{m}{ {s}^{2} } [/tex]

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