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Sagot :
Answer:
Correct option is
C
2
n
−1
Given that f(n+1)=2f(n)+1,n≥1.
Therefore, f(2)=2f(1)+1
Since f(1)=1, we have
f(2)=2f(1)+1=2(1)+1=3=2
2
−1.
Similarly f(3)=2f(2)+1=2(3)+1=7=2
3
−1
and so on....
In general, f(n)=2
n
−1
Was this answer helpful?Correct option is
C
2
n
−1
Given that f(n+1)=2f(n)+1,n≥1.
Therefore, f(2)=2f(1)+1
Since f(1)=1, we have
f(2)=2f(1)+1=2(1)+1=3=2
2
−1.
Similarly f(3)=2f(2)+1=2(3)+1=7=2
3
−1
and so on....
In general, f(n)=2
n
−1
Was this answer helpful?
Step-by-step explanation:
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