Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
A) The center of gravity of the two joined beams is;
(x, y) = (25/44), (19/88)
B) The gravitational torque on the joined beams about an axis through the corner is;
τ = 245 N.m
We are given;
Mass of vertical beam; m₂ = 19 kg
Mass of horizontal beam, m₁ = 25 kg
Length of horizontal beam; L₁ = 2 m
Length of vertical beam; L₂ = 1 m
A) Formula for center of gravity of the two joined beams is;
(x, y) = [(m₁x₁ + m₂x₂)/(m₁ + m₂)], [(m₁y₁ + m₂y₂)/(m₁ + m₂)]
Where;
(x₁, y₁) is the center of gravity on the horizontal beam
(x₂, y₂) is the center of gravity on the vertical beam
(x₁, y₁) = (L₁/2, 0)
Plugging in the relevant values gives;
(x₁, y₁) = (2/2, 0)
(x₁, y₁) = (1, 0)
(x₂, y₂) = (0, L₂/2)
Plugging in the relevant values gives;
(x₂, y₂) = (0, 1/2)
(x₂, y₂) = (0, 0.5)
Thus, center of gravity of the 2 joined beams is;
(x, y) = [((25 × 1) + (19 × 0))/(25 + 19)], [((25 × 0) + (19 × 0.5)))/(25 + 19)]
(x, y) = (25/44), (19/88)
B) Formula for the gravitational torque on the joined beams about an axis through the corner is given as;
τ = (m₁g)x₁ + (m₂g)x₂
Plugging in the relevant values;
τ = (25 × 9.8)1 + (19 × 9.8)0
τ = 245 N.m
Read more at; https://brainly.com/question/14825257
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.
