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Sagot :

Answer:

Theoretical yield = 6.27

Percentage yield = 92%

Explanation:

2KOH + CO2 - K2CO3 + H2O

Theoretical yield =

Mr of 2KOH = 56g

5.09 / 56 = 0.09 moles of 2KOH

0.09 / 2 = 0.045 moles of K2CO3

Mr of K2CO3 = 138g

138 * 0.045 = 6.27

Percentage yield = 5.80/6.27 = 0.92

0.92 * 100 = 92%