Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

An object moves according to the distance (s) in feet, time (tin seconds equation:
s(t) = - 4t ^ 2 + 237t + 744
Find the time to reach maximum height . Find the maximum height .


Sagot :

s1m1

Answer:

Step-by-step explanation:

The max is a point with coordinates (-b/2a, s(-b/2a))

s(t) = - 4t ² + 237t + 744

-b/2a = -237 /2*(-4)= 237 / 8 ≈29.625

s(237/8) =  -4(237/8)² +237*237/8 +744

              = -(237²/ 16 ) +(237²/8 ) +744

              ≈4254.563

The time when the maximum height is reached  is t ≈ 29.625 seconds

The maximum hight is at s(t) ≅4,254.563 feet

View image s1m1
We hope this was helpful. Please come back whenever you need more information or answers to your queries. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.